2k(k+7)=2k^2+2(7)k

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Solution for 2k(k+7)=2k^2+2(7)k equation: 


Simplifying
2k(k + 7) = 2k2 + 2(7) * k

Reorder the terms:
2k(7 + k) = 2k2 + 2(7) * k
(7 * 2k + k * 2k) = 2k2 + 2(7) * k
(14k + 2k2) = 2k2 + 2(7) * k

Multiply 2 * 7
14k + 2k2 = 2k2 + 14k

Reorder the terms:
14k + 2k2 = 14k + 2k2

Add '-14k' to each side of the equation.
14k + -14k + 2k2 = 14k + -14k + 2k2

Combine like terms: 14k + -14k = 0
0 + 2k2 = 14k + -14k + 2k2
2k2 = 14k + -14k + 2k2

Combine like terms: 14k + -14k = 0
2k2 = 0 + 2k2
2k2 = 2k2

Add '-2k2' to each side of the equation.
2k2 + -2k2 = 2k2 + -2k2

Combine like terms: 2k2 + -2k2 = 0
0 = 2k2 + -2k2

Combine like terms: 2k2 + -2k2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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